-3[2n-(n+1)]=

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Solution for -3[2n-(n+1)]= equation:


Simplifying
-3[2n + -1(n + 1)] = 0

Reorder the terms:
-3[2n + -1(1 + n)] = 0
-3[2n + (1 * -1 + n * -1)] = 0
-3[2n + (-1 + -1n)] = 0

Reorder the terms:
-3[-1 + 2n + -1n] = 0

Combine like terms: 2n + -1n = 1n
-3[-1 + 1n] = 0
[-1 * -3 + 1n * -3] = 0
[3 + -3n] = 0

Solving
3 + -3n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -3n = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -3n = 0 + -3
-3n = 0 + -3

Combine like terms: 0 + -3 = -3
-3n = -3

Divide each side by '-3'.
n = 1

Simplifying
n = 1

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